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Magnetic Quantum Number

The maximum n...

Question

The maximum number of electrons with spin value +1/2 in the orbital with azimuthal quantum number value l = 2 and magnetic quantum number m= +2 is ............... .

5

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6

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3

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1

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Solution

The correct option is B $1$
$s = + 1 / 2, l = 2, m = + 2$
Unique quantum number
$m a x i m u m n o o f e l e c t r o n = 1$

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Similar questions

For $_{24} C r$ , which of the following statements is/are correct:

0

n + 1

3

(+ \frac{1}{2}, 0, - \frac{1}{2})

3

m_{s} = + \frac{1}{2}

(n)

(l)

(m)

S

t

u

S = 1, 2, 3 \dots \dots

t = (S^{2} - 1^{2}), (S^{2} - 2^{2}), (S^{2} - 3^{2}) \dots \dots

u = - \frac{(t + 1)}{2}

\frac{(t + 1)}{2}

(S + t)

(n + l)

S = 2

t = 3

Z = 24

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