The maximum number of isomeric ethers with the molecular formula $C_{4} H_{10} O$ is:

2

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3

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4

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5

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Solution

The correct option is B $3$
$C_{4} H_{10}$ $\Rightarrow$ ${C H}_{3} - {C H}_{2} - {C H}_{2} - O - {C H}_{2}$
${C H}_{3} - C | {C H}_{3} H - O - {C H}_{3}$
${C H}_{3} - {C H}_{2} - O - {C H}_{2} - {C H}_{3}$

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