The maximum number of valence electrons possible for atoms in the second period of the periodic table is :

2

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8

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18

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32

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Solution

The correct option is B $8$
In the second period, we have $2 s$ and $2 p$ orbitals, which can accomodate a maximum of $(2 + 6) = 8$ electrons. Hence, maximum number of valence electrons is $8.$

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