The maximum number of zeroes the polynomial $x^{7}$ + $x^{5}$ + $x^{3}$ + x + 1 can have is

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
7

The maximum number of zeroes a polynomial can have is the degree of the polynomial itself. Since, the degree of the polynomial is seven; therefore the maximum number of zeroes would be seven.

Suggest Corrections

Similar questions

Q. The number of zeroes, the polynomial

x^{7} + x^{5} + x^{3} + x + 1

can have is equal to .

The maximum number of zeroes the polynomial $x^{7} + x^{5} + x^{3} + x + 1$ can have is _______.

Q. The expression

P (x) = {(\sqrt{x^{5} - 1} + x)}^{7} - {(\sqrt{x^{5} - 1} - x)}^{7}

is a polynomial of degree

What is the degree of the polynomial P(x) = 11 $x^{6}$ + $x^{5}$ + 3 $x^{4}$ + $x^{3}$ + $x^{2}$ + x +1, also find the maximum number of zeroes it can have

Q. The maximum number of the zeros of the polynomial

p (x) = x^{5} - 2 x + 1

is ______.

Join BYJU'S Learning Program

The maximum number of zeroes the polynomial x7+ x5 + x3 + x + 1 can have is

The correct option is A 7 The maximum number of zeroes a polynomial can have is the degree of the polynomial itself. Since, the degree of the polynomial is seven; therefore the maximum number of zeroes would be seven.

The maximum number of zeroes the polynomial $x^{7}$ + $x^{5}$ + $x^{3}$ + x + 1 can have is

The correct option is A
7

The maximum number of zeroes a polynomial can have is the degree of the polynomial itself. Since, the degree of the polynomial is seven; therefore the maximum number of zeroes would be seven.