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Question

The maximum pH of a solution containing 0.10 M Mg2+ from which, Mg(OH)2 is not precipitated is:
Given: Ksp for Mg(OH)2=1.2×1011 M3

A
4.96
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B
6.96
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C
7.04
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D
9.04
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Solution

The correct option is D 9.04
The expression for the solubility product is given below:

Ksp=[Mg2+][OH]2
Substituting values in the above expression, we get
1.2×1011=0.10×[OH]2
[OH]2=1.2×1010
[OH]=1.2×1010=1.09×105
pOH=log [OH]=log (1.09×105)=4.96
pH=14pOH=144.96=9.04

Hence, the maximum pH of the solution should be 9.04.

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