The correct option is A 3
Let f(x)=x5−6x2−4x+5=0
Then the number of change of sign in f(x) is 2 therefore f(x) can have at most two positive real roots .
Now, f(−x)=−x5−6x4+4x+5=0
Then the number of change of sign is 1.
Hence f(x) can have at most one negative real root.
So, maximum possible number of real roots is 3.