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Question

The maximum possible number of real roots of equation x56x24x+5=0 is

A
3
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B
4
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C
5
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D
0
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Solution

The correct option is A 3
Let f(x)=x56x24x+5=0
Then the number of change of sign in f(x) is 2 therefore f(x) can have at most two positive real roots .

Now, f(x)=x56x4+4x+5=0
Then the number of change of sign is 1.
Hence f(x) can have at most one negative real root.

So, maximum possible number of real roots is 3.

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