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Question

The maximum reduction in cross-sectional area per pass (R) of a cold wire drawing process is

R = 1e(n+1)

where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is

A
0.865
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B
0.826
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C
0.777
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D
0.632
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Solution

The correct option is D 0.632
Given:

Maximum reduction in cross sectional area per pass,

R=1e(n+1)

For perfectly plastic material, strain hardening coefficient n will be zero.

So, R=1e(0+1)

=1e1=0.632

Maximum reduction per pass,

R = 0.632

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