The maximum speed of a car on a road turn of radius $30 m$ , if the coefficient of friction between the tyres and the road is $0.4$ , will be

9.84 m / s

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10.84 m / s

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7.84 m / s

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5.84 m / s

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Solution

The correct option is B $10.84 m / s$
Given : $r = 30$ m $μ = 0.4$ $g = 9.8 m / s^{2}$
The maximum speed $v_{m a x} = \sqrt{μ g r} = \sqrt{0.4 \times 9.8 \times 30} = 10.84$ $m / s$

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The maximum speed of a car on a road turn of radius 30m, if the coefficient of friction between the tyres and the road is 0.4, will be

The correct option is B 10.84m/sGiven : r=30 m μ=0.4 g=9.8m/s2The maximum speed vmax=√μgr=√0.4×9.8×30=10.84 m/s

The maximum speed of a car on a road turn of radius $30 m$ , if the coefficient of friction between the tyres and the road is $0.4$ , will be

The correct option is B $10.84 m / s$
Given : $r = 30$ m $μ = 0.4$ $g = 9.8 m / s^{2}$
The maximum speed $v_{m a x} = \sqrt{μ g r} = \sqrt{0.4 \times 9.8 \times 30} = 10.84$ $m / s$