Question

The maximum speed of a particle executing $SHM$ is $1m/s$ and maximum acceleration is $1.57m/s^2$. Its time period is

• A. $1s$
• B. $4s$
• C. $2s$
• D. $3s$

Answer 1

The correct option is B $4s$

Maximum speed $V=Aw$

So, $1=Aw$

Also, maximum acceleration $a=A{w}^2$

So, $1.57=A{w}^2$

Or $\frac{1.57}{1}=\frac{A{w}^2}{Aw}$

$⟹w=1.57$

So, $\frac{2\pi }{T}=1.57$

$⟹T=\frac{2\pi }{1.57}=4s$