The maximum speed with which a car can be driven around a curve of radius $18 m$ without skidding when $g = 10 m / s^{2}$ and coefficient of friction between rubber tyres and the roadway is $0.2$ , is:

36 k m p h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18 k m p h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

21.6 k m p h

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

14.4 k m p h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $21.6 k m p h$
Centripetal force = Frictional force
$\Rightarrow$ $\frac{m v^{2}}{r} = μ m g$
or, $v = \sqrt{μ r g}$
or, $v = \sqrt{0.2 \times 18 \times 10}$
or, $v = 6 m / s$
$v = 21.6 k m p h$

Suggest Corrections

Similar questions

Q. What should be the maximum speed with which a car can be driven through a curve of radius

18 m

without skidding (where,

g = 10 m s^{- 2}

, coefficient of static friction between the rubber tyres and the roadway is

0.2

The coefficient of friction between the tyres and the road is 0.25. The maximum speed with which a car can be driven round a curve of radius 40 m without skidding is $(a s s u m e g = 10 m s^{- 2})$

Q. A car driven round curved path of radius

18 m

without the danger of skidding. The coefficient of friction between the tyres of the car and the surface of the curved path is

0.5

. What is the maximum speed in kmph of the car for safe driving nearly? (

g = 10 {m s}^{- 2}

)

Q. The coefficient of friction between the tryes and the road is 0.25. the maximum speed with which a car can be driven round a curve of radius 40 m without skidding is (assume g= 10

m s^{- 2}

)

Join BYJU'S Learning Program

The maximum speed with which a car can be driven around a curve of radius 18 m without skidding when g=10 m/s2 and coefficient of friction between rubber tyres and the roadway is 0.2, is:

The correct option is C 21.6 kmphCentripetal force = Frictional force⇒ mv2r=μmgor, v=√μrgor, v=√0.2×18×10or, v=6 m/sv=21.6 kmph

The maximum speed with which a car can be driven around a curve of radius $18 m$ without skidding when $g = 10 m / s^{2}$ and coefficient of friction between rubber tyres and the roadway is $0.2$ , is:

The correct option is C $21.6 k m p h$
Centripetal force = Frictional force
$\Rightarrow$ $\frac{m v^{2}}{r} = μ m g$
or, $v = \sqrt{μ r g}$
or, $v = \sqrt{0.2 \times 18 \times 10}$
or, $v = 6 m / s$
$v = 21.6 k m p h$