The maximum speed with which a car can be driven round a curve of radius $18$ m without skidding (when $g = 10 m s^{- 2}$ and the coefficient of friction between rubber tyres and the roadway is 0.2) is:

36.0

kmph

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18.0

kmph

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21.6

kmph

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14.4

kmph

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Solution

The correct option is C $21.6$ kmph
$R = 18 m$ , $μ = 0.2$
$V^{2} = μ g R$
$V = \sqrt{(0.2) (18) (10)}$
= $6 m / s$
$V = 6 \times \frac{18}{5} k m / h$
= $21.6 k m / h$

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The maximum speed with which a car can be driven round a curve of radius 18 m without skidding (when g=10ms−2 and the coefficient of friction between rubber tyres and the roadway is 0.2) is:

The correct option is C 21.6 kmphR=18 m , μ=0.2V2=μ g RV=√(0.2)(18)(10)=6 m/sV=6×185 km/h= 21.6 km/h

The maximum speed with which a car can be driven round a curve of radius $18$ m without skidding (when $g = 10 m s^{- 2}$ and the coefficient of friction between rubber tyres and the roadway is 0.2) is:

The correct option is C $21.6$ kmph
$R = 18 m$ , $μ = 0.2$
$V^{2} = μ g R$
$V = \sqrt{(0.2) (18) (10)}$
= $6 m / s$
$V = 6 \times \frac{18}{5} k m / h$
= $21.6 k m / h$