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Byju's Answer
Standard XII
Mathematics
Range of Trigonometric Expressions
The maximum v...
Question
The maximum value of
3
cos
θ
+
5
sin
(
θ
−
π
6
)
for any real value of
θ
is:
A
√
79
2
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B
√
19
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C
√
31
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D
√
34
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Solution
The correct option is
B
√
19
Let
μ
=
3
cos
θ
+
5
sin
(
θ
−
π
6
)
=
3
cos
θ
+
5
sin
θ
.
cos
π
6
−
5
cos
θ
.
sin
π
6
=
1
2
cos
θ
+
5
√
3
2
sin
θ
∴
max
μ
=
⎷
(
1
2
)
2
+
(
5
√
3
2
)
2
=
√
19
Suggest Corrections
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