The maximum value of $4 s i n^{2} x + 3 c o s^{2} x$ is

[Karnataka CET 2003]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
4

f(x) = $4 s i n^{2} x + 3 c o s^{2} x s i n^{2} x + 3$ and $0 \leq | s i n x | \leq 1$

∴ Maximum value of $s i n^{2} x + 3$ is 4.

Suggest Corrections

Similar questions

4 {sin}^{2} x + 3 {cos}^{2} x + sin \frac{x}{2} + cos \frac{x}{2}

f (x) = 3 cos^{2} x + 4 sin^{2} x + cos \frac{x}{2} + sin \frac{x}{2}

4 {sin}^{2} x + 3 {cos}^{2} x + sin \frac{x}{2} + cos \frac{x}{2}

4 {sin}^{2} x + 3 {cos}^{2} x

The maximum value of 3cos $θ$ - 4 sin $θ$ is

[Karnataka CET 2004]

Join BYJU'S Learning Program