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B
10
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C
11
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D
−1
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Solution
The correct option is B10 f(θ)=5cos(θ)+3cos(θ+π3)+3 =5cosθ+32cosθ−3√32sinθ+3 =132cosθ−3√32sinθ+3 Maximum value of acosθ+bsinθ+c=√a2+b2+c So, maximum value of f(θ)=10