The maximum value of 5 e - xlog x - for 0 - x - 1 is

f(x)=5e| xlog x nbsp;| 0 lt;x≤ 1 for max of f(x) , f'(x)=0 f'(x)=5e| (log x +x. 1 x ) | =0 log x = 1 x= 1 e ...

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Chain Rule of Differentiation

The maximum v...

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The maximum value of $5 e | x log x |$ for $0 < x \leq 1$ is

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\int_{0}^{\infty} \frac{x log x}{(1 + x^{2})^{2}} d x

The value of the integral $\infty \int 0 \frac{x log x}{{(1 + x^{2})}^{2}} d x$ is

\infty \int 0 \frac{x log x}{(1 + x^{2})^{2}} d x

f (x)

x = 0

f (x) = \frac{(e^{3 x} - 1) sin x}{x log (x + 1)}

x \neq 0

f (0) .

lim x \to 1 \frac{x^{x} - 1}{x log x} - lim x \to 0 \frac{log (1 - 3 x)}{x}

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