The maximum value of a.c. voltage in a circuit is 707V. Its r.m.s. value is

70.7 V

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100 V

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500 V

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707 V

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Solution

The correct option is D 500 V
As we know,
$V_{r m s} = \frac{V_{0}}{\sqrt{2}}$

$V_{r m s} = \frac{707}{\sqrt{2}} = 500 V$

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