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Byju's Answer
Standard XII
Mathematics
Range of Trigonometric Expressions
The maximum v...
Question
The maximum value of
4
sec
2
x
+
cosec
2
x
is
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Solution
4
sec
2
x
+
cosec
2
x
=
4
1
cos
2
x
+
1
sin
2
x
=
4
cos
2
x
sin
2
x
cos
2
x
+
sin
2
x
=
sin
2
2
x
So, maximum value
=
1
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