The maximum value of f(x)=3cos2x+4sin2x+cosx2+sinx2is
A
4
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B
3+√2
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C
4+√2
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D
none of these
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Solution
The correct option is C4+√2 Given, f(x)=3cos2x+4sin2x+cosx2+sinx2 =3−3sin2x+4sin2x+√(cosx2+sinx2)2 =3+sin2x+√1+sinx we know −1≤sinx≤1 Hence maximum value of f(x) is =4+√2