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Question

The maximum value of (3+4xx2+4)2+(x5)2, (where 1x3) is

A
34
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B
36
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C
32
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D
20
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Solution

The correct option is B 36
f(x)=3+4xx2+16+83+4xx2+x2+2510x
f(x)=386x+83+4xx2
f(x)=0
6+8(42x)23+4xx2=0
2(42x)3+4xx2=3
4(42x)2=9(3+4xx2)
64+16x264x=27+36x9x2
25x2100x+91=0
25x265x35x+91=0
5x(5x13)7(5x13)=0
x=75,x=135
mass x=75
Mass value=
3+4.75(75)2+42+(75.5)2
(3+2854925+4)2+(185)2
(10497525+4)2+(185)2
(45+4)2+(185)2
(245)2+(185)2
=576+32425
=90025
=36.

1093284_1157538_ans_23d3e451f87847ada06de6ae206b9bd1.jpg

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