You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Physics

Limiting Friction

The maximum v...

Question

The maximum value of mass of block $C$ so that neither $A$ nor $B$ moves is (Given that mass of $A$ is $100 k g$ and that of $B$ is $140 k g$ . Pulleys are smooth and friction coefficient between $A$ and $B$ and between $B$ and horizontal surface is :( $μ = 0.3, g = 10 m / s^{2}$ ).

210 k g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

190 k g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

185 k g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

162 k g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $162 k g$

$μ = 0.3$
$M_{A} = 100 k g$
$M_{B} = 140 k g$
From the F.B. D of the blocks:
$T "= M_{c} g$
$T^{'} = 2 T$
$T = μ M_{A} g$
$T "= μ M_{A} g + 2 μ M_{A} g + μ [M_{A} + M_{B}] g$
$= μ g [4 M_{A} + M_{B}]$
$M_{c} g = 0.3 g [4 \times 100 + 140]$
$M_{c} = 0.3 [540]$
$= 3 \times 54$
$= 162 k g$

Suggest Corrections

Similar questions

Q. The maximum value of mass of block

C

so that neither

A

nor

B

moves is (Given that mass of

A

100 k g

and that of

B

140 k g

. Pulleys are smooth and friction coefficient between

A

and

B

and between

B

and horizontal surface is :(

μ = 0.3, g = 10 m / s^{2}

Q. Find the maximum value of mass of block

C

in kg so that neither

A

nor

B

moves, (

m_{A} = 100 kg, m_{B} = 200 kg

). Pulleys and strings are massless. Coefficient of friction between

A

and

B

and between

B

and horizontal surface is

μ = 0.4

(Take $g = 10 {ms}^{- 2}$ )

Q. In the arrangement shown in figure

m_{A} = m_{B} = 2 k g

. String is massless and pulley is frictionless. Block B is resting on a smooth horizontal surface, while friction coefficient between blocks A and B is

μ = 0.5

. The maximum horizontal force

F

that can be applied so that block A does not slip over the block B is.

(g = 10 m / s^{2})

Q. The block

B

has a mass of

10 kg

. The coefficient of friction between block

B

and the surface is

μ = 0.5

. Determine the acceleration of the block

A

of mass

16 kg

. Neglect the mass of the pulleys and cords. (Take

g = 10 {m/s}^{2})

Q. Three blocks A, B and C of masses

2 kg, 3 kg

and

4 kg

are placed as shown. Coefficient of friction between A and B is 0.5 and that between B and C is 0.1. The surface is frictionless. The maximum force

F

in N that can be applied horizontally onto A such that the three blocks move together is (Answer upto 2 decimal places and take

g = 10 m s^{- 2}

)

Join BYJU'S Learning Program

The maximum value of mass of block C so that neither A nor B moves is (Given that mass of A is 100 kg and that of B is 140 kg. Pulleys are smooth and friction coefficient between A and B and between B and horizontal surface is :(μ=0.3,g=10 m/s2).

The correct option is D 162 kg μ=0.3 MA=100 kg MB=140 kg From the F.B. D of the blocks: T"=Mcg T′=2T T=μMAg T"=μMAg+2μMAg+μ[MA+MB]g =μg[4MA+MB] Mcg=0.3g[4×100+140] Mc=0.3[540] =3×54 =162 kg

The maximum value of mass of block $C$ so that neither $A$ nor $B$ moves is (Given that mass of $A$ is $100 k g$ and that of $B$ is $140 k g$ . Pulleys are smooth and friction coefficient between $A$ and $B$ and between $B$ and horizontal surface is :( $μ = 0.3, g = 10 m / s^{2}$ ).