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Question

The maximum value of log10100(1x2+x+1) is k. Then the value of log(1k) - log3 is


A

Positive

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B

Negative

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C

Zero

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D

Can’t say

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Solution

The correct option is B

Negative


log10100(1x2+x+1)=2(x2+x+1)=2((x+(12))2+(34)=(83)k=(83)log(1k)log3=log(38)log3=log 8


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