The maximum value of log10100(1x2+x+1) is k. Then the value of log(1k) - log3 is
Positive
Negative
Zero
Can’t say
log10100(1x2+x+1)=2(x2+x+1)=2((x+(12))2+(34)=(83)k=(83)log(1k)−log3=log(38)−log3=−log 8