The maximum value of sin^–1x + tan^–1x is

sin^–1x + tan^–1x का अधिकतम मान है

\frac{π}{4}

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\frac{π}{2}

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\frac{3 π}{4}

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Solution

The correct option is C $\frac{3 π}{4}$
Solution

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Similar questions

\frac{\sqrt{3}}{2}

\frac{\sqrt{3}}{2}

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\frac{3 π}{4}

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