Question

The maximum value of $sin(x+\frac{\pi }{6})+cos(x+\frac{\pi }{6})$ in the

interval $(0,\frac{\pi }{2})$ is attained at

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

$\sqrt{2}cos(x+\frac{\pi }{6}-\frac{\pi }{4})$ = $\sqrt{2}cos(x-\frac{\pi }{12})$.

Hence maximum value will be at x = $\frac{\pi }{12}$.