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Question

The maximum value of the expression 1sin2θ+3sinθcosθ+5cos2θ is

A
2
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B
3
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C
12
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D
13
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Solution

The correct option is A 2
Ans. Ans. (a).
f(θ)=1sin2θ+3sinθcosθ+5cos2θ
=11cos2θ2+32sin2θ+5(1+cos2θ)2
=26+3sin2θ+4cos2θ
Hence, [f(θ)]maximum=265=2

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