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Byju's Answer
Standard XII
Mathematics
Principal Solution of Trigonometric Equation
The maximum v...
Question
The maximum value of the expression
1
sin
2
θ
+
3
sin
θ
cos
θ
+
5
cos
2
θ
is
A
2
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B
3
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C
1
2
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D
1
3
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Solution
The correct option is
A
2
Ans. Ans.
(
a
)
.
f
(
θ
)
=
1
sin
2
θ
+
3
sin
θ
cos
θ
+
5
cos
2
θ
=
1
1
−
cos
2
θ
2
+
3
2
sin
2
θ
+
5
(
1
+
cos
2
θ
)
2
=
2
6
+
3
sin
2
θ
+
4
cos
2
θ
Hence,
[
f
(
θ
)
]
m
a
x
i
m
u
m
=
2
6
−
5
=
2
Suggest Corrections
0
Similar questions
Q.
If
1
+
sin
2
θ
=
3
sin
θ
cos
θ
, then prove that
tan
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=
1
o
r
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Q.
Prove that:
[
1
+
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tan
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]
[
1
+
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cot
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]
=
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Q.
Question 3
The value of the expression
c
o
s
e
c
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∘
+
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)
−
s
e
c
(
15
∘
−
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)
−
t
a
n
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t
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(B) 0
(C) 1
(D)
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Q.
Write the value of
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.
Q.
Show that for all real values of
θ
, the expression a
sin
2
θ
+
b
sin
θ
cos
θ
+
c
cos
2
θ
lies between
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2
(
a
+
c
)
−
1
2
√
b
2
+
(
a
−
c
)
2
1
2
(
a
+
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+
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