CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The maximum value of the function x3+x2+x-4 is


A

127

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Does not have a maximum value

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

Does not have a maximum value


Explanation for the correct option:

Find the critical points of the given function.

A function f(x)=x3+x2+x-4 is given.

Differentiate the given function with respect to x.

f'(x)=3x2+2x+1

Put f'(x) equal to zero to find the critical points.

3x2+2x+1=0x=-2±22-4(3)2·3x=-2±4-126x=-2±-86x=-2±22i6

Since, f(x) has no real critical point.

Therefore, the given function x3+x2+x-4 does not have a maximum value.

Hence, option C is the correct answer.


flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Quadratic Equations and Polynomials
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon