The maximum value of the sum of the A.P. 50, 48, 46, 44, .......... is

325

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648

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650

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652

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Solution

The correct option is C 650
Given AP is $50, 48, 46, 44, . . . . . .$
$a = 50, d = - 2$
$\Rightarrow T_{n} = a + (n - 1) d = - 2 n + 52$
$T_{n} = 0$ $\Rightarrow n = 26$
$∴$ Maximum sum $S = \frac{26}{2} (50 + 0) = 650$
Hence, option C.

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The runs scored by two batsmen A and B in six innings are given as follows:

Batsman A	48	50	54	46	48	54
Batsman B	46	44	43	46	45	46

Determine (i) Who is a better run getter? (ii) Who is a consistent player?

46, 44, 42, 54, 52, 60, 50, 58, 56, 62, 50, 56, 54, 58

48

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