The maximum value of z-6xy - y- - where 3x - 4y -0 and y-0 is -

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Finding Solution of an Equation by Trial and Error Method

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Question

the maximum value of z=6xy + y² , where 3x + 4y <=100 , and 4x +3y<= 75 for x >=0 and y>=0 is ??

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z

z = 6 x y + y^{2},

3 x + 4 y \leq 100

4 x + 3 y \leq 75

x \geq 0

y \geq 0

3 x + 4 y, 4 x + 3 y

5 x + 5 y

x, y > 0.

z = 3 x + 4 y

x - y \leq - 1, - x + y \leq 0, x, y \geq 0

\begin{matrix} x - 2 y + k z = 1 2 x + y + z = 2 3 x - y - k z = 3 \end{matrix}

(x, y, z), z \neq 0

(x, y)

Maximum and minimise Z =3x -4y subject to $x - 2 y \leq 0, - 3 x + y \leq 4, x - y \leq 6$ and $x, y \geq 0$

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