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Question

The maximum value of z in the following equation z=6xy+y2, where 3x+4y100 and 4x+3y75 for x0 and y0 is

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Solution

x0,y0
4x+3y75
3x+4y100
Plotting the lines

Checking z=6xy+y2 at (0,0),(0,25) and (754,0)
z1=0z2=625z3=0
Hence, the maximum value of z is 625.

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