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Byju's Answer
Standard XII
Physics
Uniform Circular Motion
The maximum v...
Question
The maximum velocity attained by the car is:
A
α
β
2
(
α
+
β
)
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B
α
β
α
+
β
t
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C
2
α
β
α
+
β
t
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D
4
α
β
α
+
β
t
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Solution
The correct option is
B
α
β
α
+
β
t
Let
t
1
&
t
2
be the time acceleration and deceleration respectively.
Total time elapsed
=
t
acceleration
=
α
u
=
0
deceleration
=
β
V
=
u
+
a
t
⇒
V
=
0
+
α
t
1
Let
V
be the maximum velocity
t
1
+
t
2
=
t
α
=
V
t
1
β
=
V
t
2
⇒
t
1
=
V
α
;
t
2
=
V
β
t
=
t
1
+
t
2
t
=
V
α
+
V
β
⇒
t
=
V
(
α
+
β
α
β
)
⇒
V
=
(
α
β
α
+
β
)
t
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0
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