Question

The maximum velocity of a particle, executing simple harmonic motion with an amplitude $7mm$, is $4.4m/s$. The period of oscillation is

• A. $100s$
• B. $0.01s$
• C. $10s$
• D. $0.1s$

Answer 1

The correct option is B $0.01s$

For a SHM, $x=A\sin (\omega t+\varphi )$

Velocity, $v=\frac{dx}{dt}=A\omega \cos (\omega t+\varphi )$

So, $v_{max}=A\omega$

or $4.4=7\times {10}^{-3}\left(2\pi /T\right)$

or $T=9.99\times {10}^{-3}=10\times {10}^{-3}=0.01s$