The Mean and variance of 7 observations are 8 and 16 respectively. If 5 observations are 2,4,10,12,14 find theremaining two observations
A
3,4
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B
6,8
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C
5,13
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D
3,8
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Solution
The correct option is B 6,8 Mean = 8 ⇒ x + y = 14 (assume unknown observations as x & y) Variance=16⇒x2+y2=100 ∴(x+y)2+(x−y)2=2(x2+y2) ⇒(x−y)2=4⇒x−y=±2 ∴onsolvingx+y=14andx−y=±2,wehave x=6,y=8(or)x=8,y=6