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Byju's Answer
Standard XII
Mathematics
Probability Distribution
The mean and ...
Question
The mean and variance of a Binomial distribution is
4
and
3
respectively. Find its parameters.
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Solution
Fact: In binomial distribution, mean
=
n
p
and variance
=
n
p
q
Here given
n
p
=
4
and
n
p
q
=
3
So
q
=
3
4
⇒
p
=
1
−
p
=
1
4
n
p
=
1
4
⇒
n
(
1
4
)
=
4
⇒
n
=
16
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