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Question

The mean and variance of a random variable X having a binomial distribution are 6 and 3 respectively. The probability of variable X less than 2 is

A
132048
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B
134096
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C
154096
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D
252048
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Solution

The correct option is B 134096
We know that, mean and variance of binomial distribution are given by
np=6 and npq=3 respectively.
Solving, we get
q=12, p=12, n=12

Therefore, probability of variable X less than 2 is given by
12C0 p0q12+12C1 p1q11
=(12)12+12×(12)1(12)11
=13212=134096

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