Standard Deviation about Mean for Continuous Frequency Distributions
The mean and ...
Question
The mean and variance of a random variable X having a binomial distribution are 6 and 3 respectively. The probability of variable X less than 2 is
A
132048
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B
134096
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C
154096
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D
252048
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Solution
The correct option is B134096 We know that, mean and variance of binomial distribution are given by np=6 and npq=3 respectively. Solving, we get q=12,p=12,n=12
Therefore, probability of variable X less than 2 is given by 12C0p0q12+12C1p1q11 =(12)12+12×(12)1(12)11 =13212=134096