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Question

The mean and variance of Binomial random variable X are respectively 4 and 1. Then probability that X takes the value greater than 1 is


A
(34)16
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B
(34)14.14
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C
147416
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D
149416
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Solution

The correct option is D 149416
Given np =4, npq =1 q=14p=34p=34n=16
Binomial distribution is p(x=r)=16Crprq16r r=0,1,2,....16
Required probability = p(x > 1)
= 1 - p(x < 1)
= 1 - [p(x = 0) + p(x = 1)]
=1[q16+16pq15]
=1[q+16p]q15
=1[14+16.34](14)15=1494.(14)15=149416

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