Question

The mean deviation about the mean for the data {1,2,3,-3,-2,-1} is .

• A. 1.71
• B. 2
• C. \N
• D. 4

Answer 1

The correct option is B 2

$\mathrm{Mean}=\frac{1+2+3-1-2-3}{6}=0\mathrm{For}\mathrm{data}\mathrm{set}{x}_{1,}{x}_{2,}...,x_{n,}\mathrm{Let}\overline{x}\mathrm{be}\mathrm{the}\mathrm{mean}\mathrm{then},$$\begin{array}{ccc}& & \\ & & \\ \mathrm{Then}\mathrm{MD}\left(\mathrm{Mean}\right)& =& \frac{\left(x_1-\overline{x}\right|+\left(x_2-\overline{x}\right|+\left(x_3-\overline{x}\right|+...+\left(x_n-\overline{x}\right|}{n}\\ & & \\ & & \end{array}$
$\mathrm{MD}\left(\mathrm{Mean}\right)=\frac{\left(1\right|+\left(2\right|+\left(3\right|+\left(-1\right|+\left(-2\right|+\left(-3\right|}{6}=2$