The mean deviation of 2, 4, 6, 8, 10 about its mean is

4.2

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2.4

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3.4

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4.3

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Solution

The correct option is B 2.4
$M e a n (¯ x) = \frac{\sum x_{i}}{n} = \frac{2 + 4 + 6 + 8 + 10}{5} = 6 ∴ M . D = \frac{\sum | x_{i} - ¯ x |}{n} = \frac{| 2 - 6 | + | 4 - 6 | + | 6 - 6 | + | 8 - 6 | + | 10 - 6 |}{5} = \frac{4 + 2 + 0 + 2 + 4}{5} = \frac{12}{5} = 2.4$

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