The mean deviation of $a^{3} + b^{3} a n a^{3} + b^{3} a n d a^{3} - b^{3}$ (when (a & b>0)) is:

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Solution

Mean= $\frac{a^{3} + b^{3} + a^{3}}{2} = \frac{2 a^{3}}{2} =^{3}$
$\begin{matrix} D e v i a t i o n a^{3} + b^{3} & a^{3} - (a^{3} + b^{3}) = - b^{3} a^{3} - b^{3} & a^{3} - (a^{3} - b^{3}) = b^{3} \end{matrix}$
Mean deviation = $- \frac{b^{3} b^{3}}{2} = 0$

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