The mean deviation of a frequency dist. is equal to

\frac{\sum d_{i}}{\sum f_{i}}

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\frac{\sum | d_{i} |}{\sum f_{i}}

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\frac{\sum f_{i} d_{i}}{\sum f_{i}}

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\frac{\sum f_{i} | d_{i} |}{\sum f_{i}}

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Solution

The correct option is D $\frac{\sum f_{i} | d_{i} |}{\sum f_{i}}$
It is fundamental concept that mean deviation of any frequency distribution is given by formula $\frac{\sum f_{i} | d_{i} |}{\sum f_{i}}$

Suggest Corrections

Similar questions

d_{i}

y_{i}

f_{i}

M_{g} = x + \frac{1}{\sum f_{i}} (\sum f_{i} d_{i})

¯ ¯ ¯ x = A + \frac{\sum f_{i} d_{i}}{\sum f_{i}}, d_{i} =

¯ x = a + \frac{\sum f_{i} d_{i}}{\sum f_{i}}

d_{i}^{'} s

X = A + \frac{\sum f_{i} u_{i}}{\sum f_{i}} \times h g

u_{i} = . . . . . . . . . . . . . . . .

In the formula $¯ x = A + \frac{\sum f_{i} d_{i}}{\sum f_{i}}$ , the A stands for assumed mean.

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