Question

the mean distance between the atoms of irons is $3\times {10}^{-10}m$ and inter atomic force constant for iron is 7 N/m. the young's modulus of elasticity for iron is:

• A. $2.33\times {10}^{5}N/m^2$
• B. $23.3\times {10}^{10}N/m^2$
• C. $233\times {10}^{10}N/m^2$
• D. $2.33\times {10}^{10}N/m^2$

Answer 1

The correct option is D $2.33\times {10}^{10}N/m^2$

$\begin{array}{c}\text{Given}\\ \text{distance between atoms}=3\times {10}^{-10}m\\ \text{inter atomic force constant}=7N/m\\ \text{we know,}\\ \text{young's modulus}=\frac{\text{Interatomic force constant}}{\text{mean atomic distance}}\\ =\frac{7}{3\times {10}^{-10}}\\ textyoun{g}^{\prime }smodulus=2.33\times {10}^{10}N/m2\end{array}$