The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0∘C is 0.8×10−7m . If the number of density of molecules is , then the molecular diameter is
A
3.2nm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.3 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B Mean free path λ=0.8×10−7m number of molecules per unit volume n=2.7×1025perm3 Substituting these value in λ=1√2πnd2 we get d=√1.04×10−10m=3.2˙A