The mean height of group of 8 students is 152 cm .Two more students of heights 143 and 156 cm join the group.The new mean height of the group is

151.5 cm

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115 cm

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152 cm

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200 cm

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Solution

The correct option is A 151.5 cm
$\frac{h_{1} + h_{2} + . . . . . + h_{8}}{8} = 152$
$N e w m e a n h e i g h t = \frac{h_{1} + h_{2} + . . . . . h_{8} + 143 + 156}{10}$
$= \frac{(152 \times 8) + 143 + 156}{10}$
$= \frac{1515}{10}$
$= 151.5 c m$

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Similar questions

Q. 5 students of a class have an average height

150 cm

and variance

18 {cm}^{2}

. A new student, whose height is

156 cm

joined them. The variance

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of the height of these six students is:

Q. 5 students of a class have an average height

150 cm

and variance

18 {cm}^{2}

. A new student, whose height is

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, joined them. The variance

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of the height of these six students is:

Arrange the heights of the given students in a grouped distribution with a class interval of 5 and find the number of students whose height is more than 169cm.

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Arrange the given heights of 20 students in grouped distribution with a class interval of 5. The number of students above the height of 169cm is ___ Heights (in cm): 150, 153, 162, 170, 186, 153, 162, 180, 165, 150, 178, 156, 184, 176, 173, 186, 159, 183, 180, 156.

The mean weight of 8 students is 45.5 kilogram 2 more students having weight of 41.7 kg and 53.3 kg join the group what is the new mean weight

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The mean height of group of 8 students is 152 cm .Two more students of heights 143 and 156 cm join the group.The new mean height of the group is

The correct option is A 151.5 cmh1+h2+.....+h88=152Newmeanheight=h1+h2+.....h8+143+15610=(152×8)+143+15610=151510=151.5 cm

The correct option is A 151.5 cm
$\frac{h_{1} + h_{2} + . . . . . + h_{8}}{8} = 152$
$N e w m e a n h e i g h t = \frac{h_{1} + h_{2} + . . . . . h_{8} + 143 + 156}{10}$
$= \frac{(152 \times 8) + 143 + 156}{10}$
$= \frac{1515}{10}$
$= 151.5 c m$