The mean number of tails in three tosses of a fair coin is:
3/2
1/6
3
6
Here, n = 3 and p(tail) = p(head) = ½
So, n = 3 and p = ½, then mean number of tails = np = 3(1/2) = 3/2
1. The probablity of getting exactly 2 tails in 6 tosses of a fair coin?
2. 3 dice are rolled simultaneously the probablity that the sum of the numbers on them is 16 ?