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Question

The mean of 100 items is 49. It was found that three items which should have been 60,70,80, were wrongly read as 40,20,50 respectively. The corrected mean is


A
48
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B
82.5
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C
50
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D
80
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Solution

The correct option is C 50

Sum of 100 items
=n¯¯¯x=49×100=4900

Sum of three correct items
=60+70+80=210
Sum of items replaced
=40+20+50=110

Correct sum
=4900110+210=5000

Hence, the corrected mean
=5000100=50



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