The mean of 200 items was 50. Later on,it was discovered that the two items were misread as 92 and 8 instead of 192 and 88. Find the correct mean.

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48.8

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50.9

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Solution

The correct option is D
50.9

Mean of 200 items = 50

$∴ T o t a l = 50 \times 200 = 10000$

The number were misread as 92 and 8 instead of 192 and 88.

$∴ D i f f e r e n c e = 192 - 92 + 88 - 8 = 180$

$∴ N e w t o t a l = 10000 + 180 = 10180 a n d n e w m e a n = \frac{10180}{200} = 50.9$

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The mean of 200 items was 50. Later on,it was discovered that the two items were misread as 92 and 8 instead of 192 and 88. Find the correct mean.

The correct option is D 50.9 Mean of 200 items = 50 ∴ Total=50×200=10000 The number were misread as 92 and 8 instead of 192 and 88. ∴ Difference=192−92+88−8=180 ∴ New total=10000+180=10180and new mean=10180200=50.9

The correct option is D
50.9

Mean of 200 items = 50

$∴ T o t a l = 50 \times 200 = 10000$

The number were misread as 92 and 8 instead of 192 and 88.

$∴ D i f f e r e n c e = 192 - 92 + 88 - 8 = 180$

$∴ N e w t o t a l = 10000 + 180 = 10180 a n d n e w m e a n = \frac{10180}{200} = 50.9$