The mean of 200 values of a data was 50. It was later found that two values were wrongly read as 92 and 8 instead of 192 and 88 respectively. The correct mean is
A
51
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B
50.9
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C
50.6
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D
52.43
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Solution
The correct option is B 50.9 Thevaluesmisreadwere192and88(92and8).Differenceinthevaluesentered=100+80=180Thediferencethiscausedinthemeanof200nos=180/200=.9Soactualmean=50+.9=50.9