The correct option is D 20
Let 7 numbers be x1,x2,x3,....,x7.
Given that the mean of 7 numbers is 20.
∴x1+x2+...+x77=20
⇒x1+x2+...+x7=7×20
= 140 ........(i)
Let the three numbers included be a, b and c.
Thus, 20 = (x1+x2+...+x7)+a+b+c10 (No change is mean)
⇒20×10=140+(a+b+c) [From (i)]
⇒200=140+(a+b+c)
⇒60=a+b+c
∴ Mean of (a, b, c) =a+b+c3
=603
= 20
Hence, the correct answer is option (d).