Question

The mean of a binomial distribution is 10 and its standard deviation is 2; write the value of q.

Answer 1

$$\begin{gathered} \mathrm{Mean}\mathrm{of}\mathrm{the}\mathrm{binomial}\mathrm{distribution},\mathrm{i}.\mathrm{e}.np=10 \\ \mathrm{Variance}={\left(\mathrm{Standard}\mathrm{deviation}\right)}^2,\mathrm{i}.\mathrm{e}.npq=4 \\ \therefore q=\frac{\mathrm{Variance}}{\mathrm{Mean}}=0.4 \end{gathered}$$