The mean of a dist. is 4. if its coefficient of variation is 58%. Then the S.D. of the dist. is
A
2.23
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B
3.23
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C
2.32
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D
None of these
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Solution
The correct option is C2.32 We know if a distribution having mean ¯x and standard deviation σ then coefficient of variation =σ¯x×100 ∴σ4×100=58⇒σ=5825=2.32 Hence required standard deviation is =2.32