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Question

The mean of a set of observations x1,x2,x3,....,xn is ¯x then mean of observations xi+3i i=1,2,3,....n equals

A
¯x+3(n+1)
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B
¯x+3(n+1)2
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C
¯x+(n+1)2n
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D
None of these
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Solution

The correct option is B ¯x+3(n+1)2
Given n¯x=x1+x2+x3+...+xn
Now, new observations are x1+3.1,x2+3.2.... xn+3.n
New mean
=(x1+3)+(x2+3.2)+(x3+3.3)+.....+(xn+3.n)n
=x1+x2+x3+.....+xnn+3(1+2+3+....+n)n
=¯x+3(n+1)2

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