The mean of a set of observations x1,x2,x3,....,xn is ¯x then mean of observations xi+3i∀i=1,2,3,....n equals
A
¯x+3(n+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
¯x+3(n+1)2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
¯x+(n+1)2n
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B¯x+3(n+1)2 Given n¯x=x1+x2+x3+...+xn Now, new observations are x1+3.1,x2+3.2....xn+3.n ∴ New mean =(x1+3)+(x2+3.2)+(x3+3.3)+.....+(xn+3.n)n =x1+x2+x3+.....+xnn+3(1+2+3+....+n)n =¯x+3(n+1)2