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Standard XI

Statistics

Mean of Discrete Series

The mean of t...

Question

The mean of the data set comprising of $16$ observations is $16.$ If one of the observations valued $16,$ is deleted and three new observations valued $3, 4$ and $5$ are added to the data set, then the mean of the resultant data is

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Solution

Sum of $16$ observations $= 16 \times 16 = 256$
Sum of resultant $18$ observations $= 256 - 16 + 3 + 4 + 5$
$= 252$
Mean $= \frac{252}{18} = 14$

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The mean of the data set comprising of 16 observations is 16. If one of the observations valued 16, is deleted and three new observations valued 3,4 and 5 are added to the data set, then the mean of the resultant data is

Sum of 16 observations =16×16=256 Sum of resultant 18 observations =256−16+3+4+5 =252 Mean =25218=14

The mean of the data set comprising of $16$ observations is $16.$ If one of the observations valued $16,$ is deleted and three new observations valued $3, 4$ and $5$ are added to the data set, then the mean of the resultant data is

Sum of $16$ observations $= 16 \times 16 = 256$
Sum of resultant $18$ observations $= 256 - 16 + 3 + 4 + 5$
$= 252$
Mean $= \frac{252}{18} = 14$